Base | Representation |
---|---|
bin | 1100010010111111110011… |
… | …0010010111111111110001 |
3 | 1202212112210002222220011202 |
4 | 3010233330302113333301 |
5 | 3233004442301110213 |
6 | 44431122225220545 |
7 | 2563552446336245 |
oct | 304577462277761 |
9 | 52775702886152 |
10 | 13520503144433 |
11 | 434301660105a |
12 | 1624445191755 |
13 | 770c937c71cc |
14 | 34a5782a4425 |
15 | 186a752c0b58 |
hex | c4bfcc97ff1 |
13520503144433 has 2 divisors, whose sum is σ = 13520503144434. Its totient is φ = 13520503144432.
The previous prime is 13520503144399. The next prime is 13520503144459. The reversal of 13520503144433 is 33444130502531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13402752594529 + 117750549904 = 3660977^2 + 343148^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13520503144433 is a prime.
It is not a weakly prime, because it can be changed into another prime (13520503144333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760251572216 + 6760251572217.
It is an arithmetic number, because the mean of its divisors is an integer number (6760251572217).
Almost surely, 213520503144433 is an apocalyptic number.
It is an amenable number.
13520503144433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13520503144433 is an equidigital number, since it uses as much as digits as its factorization.
13520503144433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 13520503144433 its reverse (33444130502531), we get a palindrome (46964633646964).
The spelling of 13520503144433 in words is "thirteen trillion, five hundred twenty billion, five hundred three million, one hundred forty-four thousand, four hundred thirty-three".
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