Base | Representation |
---|---|
bin | 111110111101100100… |
… | …1100100111011110000 |
3 | 110221000000122110102010 |
4 | 1331323021210323300 |
5 | 4203402241004240 |
6 | 142040433322520 |
7 | 12524426560500 |
oct | 1757311447360 |
9 | 427000573363 |
10 | 135210094320 |
11 | 52384634104 |
12 | 22255706440 |
13 | c99a413192 |
14 | 6789419a00 |
15 | 37b546a280 |
hex | 1f7b264ef0 |
135210094320 has 480 divisors, whose sum is σ = 518182334208. Its totient is φ = 28979306496.
The previous prime is 135210094277. The next prime is 135210094321. The reversal of 135210094320 is 23490012531.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135210094321) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 61374339 + ... + 61376541.
Almost surely, 2135210094320 is an apocalyptic number.
135210094320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 135210094320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (259091167104).
135210094320 is an abundant number, since it is smaller than the sum of its proper divisors (382972239888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135210094320 is a wasteful number, since it uses less digits than its factorization.
135210094320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2557 (or 2544 counting only the distinct ones).
The product of its (nonzero) digits is 6480, while the sum is 30.
The spelling of 135210094320 in words is "one hundred thirty-five billion, two hundred ten million, ninety-four thousand, three hundred twenty".
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