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13521314249 is a prime number
BaseRepresentation
bin11001001011110111…
…01110000111001001
31021220022201221011122
430211323232013021
5210142424023444
610113412405025
7656033163152
oct144573560711
937808657148
1013521314249
11580947a583
122754316775
1313763aa481
14923aac929
155420ca4ee
hex325eee1c9

13521314249 has 2 divisors, whose sum is σ = 13521314250. Its totient is φ = 13521314248.

The previous prime is 13521314243. The next prime is 13521314251. The reversal of 13521314249 is 94241312531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11356738624 + 2164575625 = 106568^2 + 46525^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13521314249 is a prime.

Together with 13521314251, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13521314243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760657124 + 6760657125.

It is an arithmetic number, because the mean of its divisors is an integer number (6760657125).

Almost surely, 213521314249 is an apocalyptic number.

It is an amenable number.

13521314249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13521314249 is an equidigital number, since it uses as much as digits as its factorization.

13521314249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 25920, while the sum is 35.

The spelling of 13521314249 in words is "thirteen billion, five hundred twenty-one million, three hundred fourteen thousand, two hundred forty-nine".