13525433140 has 24 divisors (see below), whose sum is σ = 28438040232. Its totient is φ = 5403576960.

The previous prime is 13525433123. The next prime is 13525433147. The reversal of 13525433140 is 4133452531.

It can be written as a sum of positive squares in 4 ways, for example, as 1547006224 + 11978426916 = 39332^2 + 109446^2 .

It is a super-3 number, since 3×13525433140³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13525433147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 395439 + ... + 428278.

It is an arithmetic number, because the mean of its divisors is an integer number (1184918343).

Almost surely, 2^13525433140 is an apocalyptic number.

13525433140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13525433140 is an abundant number, since it is smaller than the sum of its proper divisors (14912607092).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13525433140 is a wasteful number, since it uses less digits than its factorization.

13525433140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 824547 (or 824545 counting only the distinct ones).

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13525433140 its reverse (4133452531), we get a palindrome (17658885671).

The spelling of 13525433140 in words is "thirteen billion, five hundred twenty-five million, four hundred thirty-three thousand, one hundred forty".