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13525439957 is a prime number
BaseRepresentation
bin11001001100010110…
…11101010111010101
31021220121111112120122
430212023131113111
5210200003034312
610114041041325
7656113225361
oct144613352725
937817445518
1013525439957
115810838257
122755786245
1313771c3313
149244642a1
15542642b72
hex3262dd5d5

13525439957 has 2 divisors, whose sum is σ = 13525439958. Its totient is φ = 13525439956.

The previous prime is 13525439933. The next prime is 13525439969. The reversal of 13525439957 is 75993452531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9115284676 + 4410155281 = 95474^2 + 66409^2 .

It is a cyclic number.

It is not a de Polignac number, because 13525439957 - 28 = 13525439701 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13525439899 and 13525439908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13525438957) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762719978 + 6762719979.

It is an arithmetic number, because the mean of its divisors is an integer number (6762719979).

Almost surely, 213525439957 is an apocalyptic number.

It is an amenable number.

13525439957 is a deficient number, since it is larger than the sum of its proper divisors (1).

13525439957 is an equidigital number, since it uses as much as digits as its factorization.

13525439957 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5103000, while the sum is 53.

The spelling of 13525439957 in words is "thirteen billion, five hundred twenty-five million, four hundred thirty-nine thousand, nine hundred fifty-seven".