Base | Representation |
---|---|
bin | 111110111111011000… |
… | …1000000111000100111 |
3 | 110221011020210210122221 |
4 | 1331332301000320213 |
5 | 4204013303422241 |
6 | 142050441533211 |
7 | 12526064344312 |
oct | 1757661007047 |
9 | 427136723587 |
10 | 135270764071 |
11 | 524059021a3 |
12 | 22271aa4207 |
13 | c9a9b65c41 |
14 | 67934cd979 |
15 | 37ba9515d1 |
hex | 1f7ec40e27 |
135270764071 has 2 divisors, whose sum is σ = 135270764072. Its totient is φ = 135270764070.
The previous prime is 135270764029. The next prime is 135270764077. The reversal of 135270764071 is 170467072531.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135270764071 - 215 = 135270731303 is a prime.
It is a super-2 number, since 2×1352707640712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135270764077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67635382035 + 67635382036.
It is an arithmetic number, because the mean of its divisors is an integer number (67635382036).
Almost surely, 2135270764071 is an apocalyptic number.
135270764071 is a deficient number, since it is larger than the sum of its proper divisors (1).
135270764071 is an equidigital number, since it uses as much as digits as its factorization.
135270764071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 246960, while the sum is 43.
The spelling of 135270764071 in words is "one hundred thirty-five billion, two hundred seventy million, seven hundred sixty-four thousand, seventy-one".
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