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13530254477 is a prime number
BaseRepresentation
bin11001001100111011…
…10100110010001101
31021220221120010212012
430212131310302031
5210202221120402
610114332151005
7656202160025
oct144635646215
937827503765
1013530254477
1158135264a3
122757308465
1313781ba84c
14924d58a85
15542c94452
hex326774c8d

13530254477 has 2 divisors, whose sum is σ = 13530254478. Its totient is φ = 13530254476.

The previous prime is 13530254467. The next prime is 13530254489. The reversal of 13530254477 is 77445203531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12139412041 + 1390842436 = 110179^2 + 37294^2 .

It is an emirp because it is prime and its reverse (77445203531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13530254477 - 216 = 13530188941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13530254467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765127238 + 6765127239.

It is an arithmetic number, because the mean of its divisors is an integer number (6765127239).

Almost surely, 213530254477 is an apocalyptic number.

It is an amenable number.

13530254477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13530254477 is an equidigital number, since it uses as much as digits as its factorization.

13530254477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 352800, while the sum is 41.

The spelling of 13530254477 in words is "thirteen billion, five hundred thirty million, two hundred fifty-four thousand, four hundred seventy-seven".