1353051452407 has 2 divisors, whose sum is σ = 1353051452408. Its totient is φ = 1353051452406.

The previous prime is 1353051452381. The next prime is 1353051452447. The reversal of 1353051452407 is 7042541503531.

It is an a-pointer prime, because the next prime (1353051452447) can be obtained adding 1353051452407 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1353051452407 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1353051452407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1353051452447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676525726203 + 676525726204.

It is an arithmetic number, because the mean of its divisors is an integer number (676525726204).

Almost surely, 2^{1353051452407} is an apocalyptic number.

1353051452407 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353051452407 is an equidigital number, since it uses as much as digits as its factorization.

1353051452407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252000, while the sum is 40.

Adding to 1353051452407 its reverse (7042541503531), we get a palindrome (8395592955938).

The spelling of 1353051452407 in words is "one trillion, three hundred fifty-three billion, fifty-one million, four hundred fifty-two thousand, four hundred seven".