Base | Representation |
---|---|
bin | 111111000000100011… |
… | …0101100100011111111 |
3 | 110221020222122022120112 |
4 | 1332001012230203333 |
5 | 4204103330034211 |
6 | 142054402540235 |
7 | 12530052021002 |
oct | 1760106544377 |
9 | 427228568515 |
10 | 135310002431 |
11 | 52425a7259a |
12 | 2228306767b |
13 | c9b5023bc6 |
14 | 67987c5539 |
15 | 37be10288b |
hex | 1f811ac8ff |
135310002431 has 2 divisors, whose sum is σ = 135310002432. Its totient is φ = 135310002430.
The previous prime is 135310002323. The next prime is 135310002433. The reversal of 135310002431 is 134200013531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135310002431 - 230 = 134236260607 is a prime.
It is a super-2 number, since 2×1353100024312 (a number of 23 digits) contains 22 as substring.
Together with 135310002433, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 135310002397 and 135310002406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135310002433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67655001215 + 67655001216.
It is an arithmetic number, because the mean of its divisors is an integer number (67655001216).
Almost surely, 2135310002431 is an apocalyptic number.
135310002431 is a deficient number, since it is larger than the sum of its proper divisors (1).
135310002431 is an equidigital number, since it uses as much as digits as its factorization.
135310002431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 135310002431 its reverse (134200013531), we get a palindrome (269510015962).
The spelling of 135310002431 in words is "one hundred thirty-five billion, three hundred ten million, two thousand, four hundred thirty-one".
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