Base | Representation |
---|---|
bin | 11001001101000011… |
… | …11001100001100111 |
3 | 1021221000120101212112 |
4 | 30212201321201213 |
5 | 210203004304341 |
6 | 10114411111235 |
7 | 656214225512 |
oct | 144641714147 |
9 | 37830511775 |
10 | 13531322471 |
11 | 5814095937 |
12 | 275774251b |
13 | 13784a29b4 |
14 | 925155d79 |
15 | 542e05aeb |
hex | 326879867 |
13531322471 has 2 divisors, whose sum is σ = 13531322472. Its totient is φ = 13531322470.
The previous prime is 13531322417. The next prime is 13531322509. The reversal of 13531322471 is 17422313531.
13531322471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with previous prime (13531322417) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13531322471 - 230 = 12457580647 is a prime.
It is a super-3 number, since 3×135313224713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531322411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765661235 + 6765661236.
It is an arithmetic number, because the mean of its divisors is an integer number (6765661236).
Almost surely, 213531322471 is an apocalyptic number.
13531322471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531322471 is an equidigital number, since it uses as much as digits as its factorization.
13531322471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15120, while the sum is 32.
The spelling of 13531322471 in words is "thirteen billion, five hundred thirty-one million, three hundred twenty-two thousand, four hundred seventy-one".
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