Base | Representation |
---|---|
bin | 10011101100001101010… |
… | …100100101001111011111 |
3 | 11210100200112020120110222 |
4 | 103230031110211033133 |
5 | 134132211334304341 |
6 | 2513342331351555 |
7 | 166522011622034 |
oct | 23541524451737 |
9 | 4710615216428 |
10 | 1353138197471 |
11 | 481954266475 |
12 | 19a2b72b25bb |
13 | 9a7a6077438 |
14 | 496c69b738b |
15 | 252e905b44b |
hex | 13b0d5253df |
1353138197471 has 2 divisors, whose sum is σ = 1353138197472. Its totient is φ = 1353138197470.
The previous prime is 1353138197449. The next prime is 1353138197557. The reversal of 1353138197471 is 1747918313531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1353138197471 - 222 = 1353134003167 is a prime.
It is a super-3 number, since 3×13531381974713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1353138197171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676569098735 + 676569098736.
It is an arithmetic number, because the mean of its divisors is an integer number (676569098736).
Almost surely, 21353138197471 is an apocalyptic number.
1353138197471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353138197471 is an equidigital number, since it uses as much as digits as its factorization.
1353138197471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1905120, while the sum is 53.
The spelling of 1353138197471 in words is "one trillion, three hundred fifty-three billion, one hundred thirty-eight million, one hundred ninety-seven thousand, four hundred seventy-one".
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