Base | Representation |
---|---|
bin | 1100010011110111011000… |
… | …0101100101011111000101 |
3 | 1202220222021220120110110002 |
4 | 3010331312011211133011 |
5 | 3233231021310003240 |
6 | 44442030524211045 |
7 | 2564621255153204 |
oct | 304756605453705 |
9 | 52828256513402 |
10 | 13535423125445 |
11 | 4349382539681 |
12 | 1627309999a85 |
13 | 7725008a7340 |
14 | 34b191a1923b |
15 | 18714a07ad15 |
hex | c4f761657c5 |
13535423125445 has 32 divisors (see below), whose sum is σ = 17569797794304. Its totient is φ = 9950950310400.
The previous prime is 13535423125387. The next prime is 13535423125463. The reversal of 13535423125445 is 54452132453531.
It is not a de Polignac number, because 13535423125445 - 212 = 13535423121349 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13535423125445.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 22978574 + ... + 23560256.
It is an arithmetic number, because the mean of its divisors is an integer number (549056181072).
Almost surely, 213535423125445 is an apocalyptic number.
It is an amenable number.
13535423125445 is a deficient number, since it is larger than the sum of its proper divisors (4034374668859).
13535423125445 is a wasteful number, since it uses less digits than its factorization.
13535423125445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 583293.
The product of its digits is 4320000, while the sum is 47.
Adding to 13535423125445 its reverse (54452132453531), we get a palindrome (67987555578976).
The spelling of 13535423125445 in words is "thirteen trillion, five hundred thirty-five billion, four hundred twenty-three million, one hundred twenty-five thousand, four hundred forty-five".
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