Base | Representation |
---|---|
bin | 1100010011111010010100… |
… | …1111001011111000100011 |
3 | 1202221001100001001202011221 |
4 | 3010332211033023320203 |
5 | 3233234131311434141 |
6 | 44442241223115511 |
7 | 2564650002014026 |
oct | 304764517137043 |
9 | 52831301052157 |
10 | 13536214171171 |
11 | 4349749013a7a |
12 | 16274aa8a2b97 |
13 | 7725c8743633 |
14 | 34b228ad31bd |
15 | 187194734bd1 |
hex | c4fa53cbe23 |
13536214171171 has 2 divisors, whose sum is σ = 13536214171172. Its totient is φ = 13536214171170.
The previous prime is 13536214171169. The next prime is 13536214171223. The reversal of 13536214171171 is 17117141263531.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13536214171171 - 21 = 13536214171169 is a prime.
It is a super-2 number, since 2×135362141711712 (a number of 27 digits) contains 22 as substring.
Together with 13536214171169, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13536214171471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6768107085585 + 6768107085586.
It is an arithmetic number, because the mean of its divisors is an integer number (6768107085586).
Almost surely, 213536214171171 is an apocalyptic number.
13536214171171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13536214171171 is an equidigital number, since it uses as much as digits as its factorization.
13536214171171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 105840, while the sum is 43.
The spelling of 13536214171171 in words is "thirteen trillion, five hundred thirty-six billion, two hundred fourteen million, one hundred seventy-one thousand, one hundred seventy-one".
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