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13536431 is a prime number
BaseRepresentation
bin110011101000…
…110010101111
3221110201111022
4303220302233
511431131211
61202044355
7223025546
oct63506257
927421438
1013536431
117706137
1246496bb
132a5c42c
141b2515d
1512c5bdb
hexce8caf

13536431 has 2 divisors, whose sum is σ = 13536432. Its totient is φ = 13536430.

The previous prime is 13536427. The next prime is 13536433. The reversal of 13536431 is 13463531.

It is a strong prime.

It is an emirp because it is prime and its reverse (13463531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13536431 - 22 = 13536427 is a prime.

It is a super-2 number, since 2×135364312 = 366469928435522, which contains 22 as substring.

Together with 13536433, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13536431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13536433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6768215 + 6768216.

It is an arithmetic number, because the mean of its divisors is an integer number (6768216).

Almost surely, 213536431 is an apocalyptic number.

13536431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13536431 is an equidigital number, since it uses as much as digits as its factorization.

13536431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3240, while the sum is 26.

The square root of 13536431 is about 3679.1889051801. The cubic root of 13536431 is about 238.3241528514.

Adding to 13536431 its reverse (13463531), we get a palindrome (26999962).

Subtracting from 13536431 its reverse (13463531), we obtain a square (72900 = 2702).

The spelling of 13536431 in words is "thirteen million, five hundred thirty-six thousand, four hundred thirty-one".