Base | Representation |
---|---|
bin | 111111000010101100… |
… | …1101110100010010000 |
3 | 110221110000022021000000 |
4 | 1332011121232202100 |
5 | 4204230304200422 |
6 | 142105500130000 |
7 | 12531615602220 |
oct | 1760531564220 |
9 | 427400267000 |
10 | 135382100112 |
11 | 52462736656 |
12 | 222a3236900 |
13 | c9c6c4845c |
14 | 67a41d2080 |
15 | 37c55e4cac |
hex | 1f8566e890 |
135382100112 has 140 divisors (see below), whose sum is σ = 449456639680. Its totient is φ = 38680576704.
The previous prime is 135382100093. The next prime is 135382100219. The reversal of 135382100112 is 211001283531.
135382100112 is a `hidden beast` number, since 1 + 3 + 538 + 2 + 10 + 0 + 112 = 666.
It is a super-3 number, since 3×1353821001123 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 747412 + ... + 910707.
Almost surely, 2135382100112 is an apocalyptic number.
135382100112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
135382100112 is an abundant number, since it is smaller than the sum of its proper divisors (314074539568).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135382100112 is an equidigital number, since it uses as much as digits as its factorization.
135382100112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1658152 (or 1658131 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 27.
Adding to 135382100112 its reverse (211001283531), we get a palindrome (346383383643).
The spelling of 135382100112 in words is "one hundred thirty-five billion, three hundred eighty-two million, one hundred thousand, one hundred twelve".
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