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13539257053 = 7471391491987
BaseRepresentation
bin11001001110000000…
…01010101011011101
31021221120111112001221
430213000022223131
5210212022211203
610115253133341
7656341533430
oct144700125335
937846445057
1013539257053
115818615243
12275a32a251
13137a02040a
1492621d817
15543971abd
hex32700aadd

13539257053 has 32 divisors (see below), whose sum is σ = 16031232000. Its totient is φ = 11195129664.

The previous prime is 13539257041. The next prime is 13539257071. The reversal of 13539257053 is 35075293531.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13539257053 is a prime.

It is a super-2 number, since 2×135392570532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13539257023) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6812926 + ... + 6814912.

It is an arithmetic number, because the mean of its divisors is an integer number (500976000).

Almost surely, 213539257053 is an apocalyptic number.

It is an amenable number.

13539257053 is a deficient number, since it is larger than the sum of its proper divisors (2491974947).

13539257053 is a wasteful number, since it uses less digits than its factorization.

13539257053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2329.

The product of its (nonzero) digits is 425250, while the sum is 43.

The spelling of 13539257053 in words is "thirteen billion, five hundred thirty-nine million, two hundred fifty-seven thousand, fifty-three".

Divisors: 1 7 47 139 149 329 973 1043 1987 6533 7003 13909 20711 45731 49021 93389 144977 276193 296063 653723 973417 1933351 2072441 6813919 12981071 13914961 41152757 90867497 97404727 288069299 1934179579 13539257053