Base | Representation |
---|---|
bin | 11001001110000110… |
… | …11011101110111111 |
3 | 1021221122010000200101 |
4 | 30213003123232333 |
5 | 210212232111333 |
6 | 10115323341531 |
7 | 656352031051 |
oct | 144703335677 |
9 | 37848100611 |
10 | 13540113343 |
11 | 581904a619 |
12 | 275a6818a7 |
13 | 137a2600b3 |
14 | 9263a38d1 |
15 | 543a9067d |
hex | 3270dbbbf |
13540113343 has 2 divisors, whose sum is σ = 13540113344. Its totient is φ = 13540113342.
The previous prime is 13540113329. The next prime is 13540113359. The reversal of 13540113343 is 34331104531.
It is a weak prime.
It is an emirp because it is prime and its reverse (34331104531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13540113343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13540113143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770056671 + 6770056672.
It is an arithmetic number, because the mean of its divisors is an integer number (6770056672).
Almost surely, 213540113343 is an apocalyptic number.
13540113343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13540113343 is an equidigital number, since it uses as much as digits as its factorization.
13540113343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 13540113343 its reverse (34331104531), we get a palindrome (47871217874).
The spelling of 13540113343 in words is "thirteen billion, five hundred forty million, one hundred thirteen thousand, three hundred forty-three".
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