Base | Representation |
---|---|
bin | 10011101101000010101… |
… | …010111001111000110101 |
3 | 11210102222220102112021111 |
4 | 103231002222321320311 |
5 | 134141030002213103 |
6 | 2514011223315021 |
7 | 166553130440221 |
oct | 23550252717065 |
9 | 4712886375244 |
10 | 1354033241653 |
11 | 482273513404 |
12 | 19a506baba71 |
13 | 9a8b9627191 |
14 | 4976d803781 |
15 | 2534c90986d |
hex | 13b42ab9e35 |
1354033241653 has 2 divisors, whose sum is σ = 1354033241654. Its totient is φ = 1354033241652.
The previous prime is 1354033241651. The next prime is 1354033241657. The reversal of 1354033241653 is 3561423304531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1265215533124 + 88817708529 = 1124818^2 + 298023^2 .
It is a cyclic number.
It is not a de Polignac number, because 1354033241653 - 21 = 1354033241651 is a prime.
Together with 1354033241651, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1354033241651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677016620826 + 677016620827.
It is an arithmetic number, because the mean of its divisors is an integer number (677016620827).
Almost surely, 21354033241653 is an apocalyptic number.
It is an amenable number.
1354033241653 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354033241653 is an equidigital number, since it uses as much as digits as its factorization.
1354033241653 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 388800, while the sum is 40.
The spelling of 1354033241653 in words is "one trillion, three hundred fifty-four billion, thirty-three million, two hundred forty-one thousand, six hundred fifty-three".
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