Base | Representation |
---|---|
bin | 10011101101000011010… |
… | …100000101010010101111 |
3 | 11210110000122201221201011 |
4 | 103231003110011102233 |
5 | 134141040233130041 |
6 | 2514012250530051 |
7 | 166553321256343 |
oct | 23550324052257 |
9 | 4713018657634 |
10 | 1354044036271 |
11 | 482279616583 |
12 | 19a50a736927 |
13 | 9a8bb936624 |
14 | 49771013623 |
15 | 2534d83ce81 |
hex | 13b435054af |
1354044036271 has 2 divisors, whose sum is σ = 1354044036272. Its totient is φ = 1354044036270.
The previous prime is 1354044036269. The next prime is 1354044036403. The reversal of 1354044036271 is 1726304404531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1354044036271 - 21 = 1354044036269 is a prime.
It is a super-2 number, since 2×13540440362712 (a number of 25 digits) contains 22 as substring.
Together with 1354044036269, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1354044036671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677022018135 + 677022018136.
It is an arithmetic number, because the mean of its divisors is an integer number (677022018136).
Almost surely, 21354044036271 is an apocalyptic number.
1354044036271 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354044036271 is an equidigital number, since it uses as much as digits as its factorization.
1354044036271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241920, while the sum is 40.
The spelling of 1354044036271 in words is "one trillion, three hundred fifty-four billion, forty-four million, thirty-six thousand, two hundred seventy-one".
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