13541322342047 has 2 divisors, whose sum is σ = 13541322342048. Its totient is φ = 13541322342046.

The previous prime is 13541322342019. The next prime is 13541322342049. The reversal of 13541322342047 is 74024322314531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13541322342047 - 2²² = 13541318147743 is a prime.

Together with 13541322342049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13541322341995 and 13541322342013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13541322342049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770661171023 + 6770661171024.

It is an arithmetic number, because the mean of its divisors is an integer number (6770661171024).

Almost surely, 2^{13541322342047} is an apocalyptic number.

13541322342047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13541322342047 is an equidigital number, since it uses as much as digits as its factorization.

13541322342047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 483840, while the sum is 41.

Adding to 13541322342047 its reverse (74024322314531), we get a palindrome (87565644656578).

The spelling of 13541322342047 in words is "thirteen trillion, five hundred forty-one billion, three hundred twenty-two million, three hundred forty-two thousand, forty-seven".