Base | Representation |
---|---|
bin | 1100010100001101010110… |
… | …1101010101111010011111 |
3 | 1202221112112001000010112021 |
4 | 3011003111231111322133 |
5 | 3233330112010201424 |
6 | 44444444141121011 |
7 | 2565220406560255 |
oct | 305032555257237 |
9 | 52845461003467 |
10 | 13541322350239 |
11 | 435092a499572 |
12 | 1628495559167 |
13 | 772c30b1a7b8 |
14 | 34b5912b45d5 |
15 | 187392e094e4 |
hex | c50d5b55e9f |
13541322350239 has 2 divisors, whose sum is σ = 13541322350240. Its totient is φ = 13541322350238.
The previous prime is 13541322350221. The next prime is 13541322350243. The reversal of 13541322350239 is 93205322314531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13541322350239 - 213 = 13541322342047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13541322350195 and 13541322350204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13541322360239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770661175119 + 6770661175120.
It is an arithmetic number, because the mean of its divisors is an integer number (6770661175120).
Almost surely, 213541322350239 is an apocalyptic number.
13541322350239 is a deficient number, since it is larger than the sum of its proper divisors (1).
13541322350239 is an equidigital number, since it uses as much as digits as its factorization.
13541322350239 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 583200, while the sum is 43.
The spelling of 13541322350239 in words is "thirteen trillion, five hundred forty-one billion, three hundred twenty-two million, three hundred fifty thousand, two hundred thirty-nine".
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