Base | Representation |
---|---|
bin | 11110110010101001000010… |
… | …010110111100110010010111 |
3 | 122202111011101110002002010222 |
4 | 132302221002112330302113 |
5 | 120222221043112432122 |
6 | 1200003425212104555 |
7 | 40344606221530445 |
oct | 3662510226746227 |
9 | 582434343062128 |
10 | 135421432155287 |
11 | 3a1709a8027613 |
12 | 132316b776515b |
13 | 5a7425628bb75 |
14 | 256260a2b1b95 |
15 | 109c950026b42 |
hex | 7b2a425bcc97 |
135421432155287 has 2 divisors, whose sum is σ = 135421432155288. Its totient is φ = 135421432155286.
The previous prime is 135421432155211. The next prime is 135421432155319. The reversal of 135421432155287 is 782551234124531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135421432155287 - 210 = 135421432154263 is a prime.
It is a super-4 number, since 4×1354214321552874 (a number of 58 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135421432155887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67710716077643 + 67710716077644.
It is an arithmetic number, because the mean of its divisors is an integer number (67710716077644).
Almost surely, 2135421432155287 is an apocalyptic number.
135421432155287 is a deficient number, since it is larger than the sum of its proper divisors (1).
135421432155287 is an equidigital number, since it uses as much as digits as its factorization.
135421432155287 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8064000, while the sum is 53.
The spelling of 135421432155287 in words is "one hundred thirty-five trillion, four hundred twenty-one billion, four hundred thirty-two million, one hundred fifty-five thousand, two hundred eighty-seven".
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