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135422504025383 is a prime number
BaseRepresentation
bin11110110010101010000010…
…001111110011110100100111
3122202111021011010222201111102
4132302222002033303310213
5120222230242012303013
61200004123422030315
740344644615344241
oct3662520217636447
9582437133881442
10135422504025383
113a1713a8079473
121323195671839b
135a74397370b23
1425626ac7ab091
15109c9b41a2d58
hex7b2a823f3d27

135422504025383 has 2 divisors, whose sum is σ = 135422504025384. Its totient is φ = 135422504025382.

The previous prime is 135422504025343. The next prime is 135422504025461. The reversal of 135422504025383 is 383520405224531.

It is a weak prime.

It is an emirp because it is prime and its reverse (383520405224531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135422504025383 - 226 = 135422436916519 is a prime.

It is a super-3 number, since 3×1354225040253833 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135422504025343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67711252012691 + 67711252012692.

It is an arithmetic number, because the mean of its divisors is an integer number (67711252012692).

Almost surely, 2135422504025383 is an apocalyptic number.

135422504025383 is a deficient number, since it is larger than the sum of its proper divisors (1).

135422504025383 is an equidigital number, since it uses as much as digits as its factorization.

135422504025383 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456000, while the sum is 47.

The spelling of 135422504025383 in words is "one hundred thirty-five trillion, four hundred twenty-two billion, five hundred four million, twenty-five thousand, three hundred eighty-three".