135431213331040 has 192 divisors, whose sum is σ = 351699304320000. Its totient is φ = 48874224199680.

The previous prime is 135431213331023. The next prime is 135431213331053. The reversal of 135431213331040 is 40133312134531.

It is a super-2 number, since 2×135431213331040² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 135431213330987 and 135431213331005.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 135746341 + ... + 136740379.

It is an arithmetic number, because the mean of its divisors is an integer number (1831767210000).

Almost surely, 2^{135431213331040} is an apocalyptic number.

135431213331040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135431213331040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (175849652160000).

135431213331040 is an abundant number, since it is smaller than the sum of its proper divisors (216268090988960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135431213331040 is a wasteful number, since it uses less digits than its factorization.

135431213331040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 994653 (or 994645 counting only the distinct ones).

The product of its (nonzero) digits is 38880, while the sum is 34.

Adding to 135431213331040 its reverse (40133312134531), we get a palindrome (175564525465571).

The spelling of 135431213331040 in words is "one hundred thirty-five trillion, four hundred thirty-one billion, two hundred thirteen million, three hundred thirty-one thousand, forty".