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1354324144053 = 3451441381351
BaseRepresentation
bin10011101101010100000…
…000100110111110110101
311210110202011210220100110
4103231110000212332311
5134142123440102203
62514100134333233
7166563262166166
oct23552400467665
94713664726313
101354324144053
11482402743711
1219a5884ba219
139a93498b08a
144979a2c976d
152536821cd03
hex13b54026fb5

1354324144053 has 4 divisors (see below), whose sum is σ = 1805765525408. Its totient is φ = 902882762700.

The previous prime is 1354324144013. The next prime is 1354324144073. The reversal of 1354324144053 is 3504414234531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1354324144053 - 225 = 1354290589621 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1354324144013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225720690673 + ... + 225720690678.

It is an arithmetic number, because the mean of its divisors is an integer number (451441381352).

Almost surely, 21354324144053 is an apocalyptic number.

It is an amenable number.

1354324144053 is a deficient number, since it is larger than the sum of its proper divisors (451441381355).

1354324144053 is an equidigital number, since it uses as much as digits as its factorization.

1354324144053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 451441381354.

The product of its (nonzero) digits is 345600, while the sum is 39.

Adding to 1354324144053 its reverse (3504414234531), we get a palindrome (4858738378584).

The spelling of 1354324144053 in words is "one trillion, three hundred fifty-four billion, three hundred twenty-four million, one hundred forty-four thousand, fifty-three".

Divisors: 1 3 451441381351 1354324144053