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1354324144052 = 2211191620004957
BaseRepresentation
bin10011101101010100000…
…000100110111110110100
311210110202011210220100102
4103231110000212332310
5134142123440102202
62514100134333232
7166563262166165
oct23552400467664
94713664726312
101354324144052
11482402743710
1219a5884ba218
139a93498b089
144979a2c976c
152536821cd02
hex13b54026fb4

1354324144052 has 24 divisors (see below), whose sum is σ = 2721608329440. Its totient is φ = 583201784160.

The previous prime is 1354324144013. The next prime is 1354324144073. The reversal of 1354324144052 is 2504414234531.

It is a Harshad number since it is a multiple of its sum of digits (38).

It is a junction number, because it is equal to n+sod(n) for n = 1354324143997 and 1354324144015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 810001643 + ... + 810003314.

It is an arithmetic number, because the mean of its divisors is an integer number (113400347060).

Almost surely, 21354324144052 is an apocalyptic number.

It is an amenable number.

1354324144052 is an abundant number, since it is smaller than the sum of its proper divisors (1367284185388).

1354324144052 is a wasteful number, since it uses less digits than its factorization.

1354324144052 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1620004991 (or 1620004989 counting only the distinct ones).

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 1354324144052 its reverse (2504414234531), we get a palindrome (3858738378583).

The spelling of 1354324144052 in words is "one trillion, three hundred fifty-four billion, three hundred twenty-four million, one hundred forty-four thousand, fifty-two".

Divisors: 1 2 4 11 19 22 38 44 76 209 418 836 1620004957 3240009914 6480019828 17820054527 30780094183 35640109054 61560188366 71280218108 123120376732 338581036013 677162072026 1354324144052