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13543303679 is a prime number
BaseRepresentation
bin11001001110011111…
…00110100111111111
31021221212010002222222
430213033212213333
5210214041204204
610115515555555
7656421116243
oct144717464777
937855102888
1013543303679
11581a929564
12275b75bbbb
13137ab09279
14926994423
15543ec0abe
hex3273e69ff

13543303679 has 2 divisors, whose sum is σ = 13543303680. Its totient is φ = 13543303678.

The previous prime is 13543303673. The next prime is 13543303723. The reversal of 13543303679 is 97630334531.

It is an a-pointer prime, because the next prime (13543303723) can be obtained adding 13543303679 to its sum of digits (44).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13543303679 is a prime.

It is a super-2 number, since 2×135433036792 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13543303673) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771651839 + 6771651840.

It is an arithmetic number, because the mean of its divisors is an integer number (6771651840).

Almost surely, 213543303679 is an apocalyptic number.

13543303679 is a deficient number, since it is larger than the sum of its proper divisors (1).

13543303679 is an equidigital number, since it uses as much as digits as its factorization.

13543303679 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 612360, while the sum is 44.

It can be divided in two parts, 1354 and 3303679, that added together give a palindrome (3305033).

The spelling of 13543303679 in words is "thirteen billion, five hundred forty-three million, three hundred three thousand, six hundred seventy-nine".