Base | Representation |
---|---|
bin | 11001001110011111… |
… | …10000011110101111 |
3 | 1021221212012011101002 |
4 | 30213033300132233 |
5 | 210214044002142 |
6 | 10115520510515 |
7 | 656421345032 |
oct | 144717603657 |
9 | 37855164332 |
10 | 13543344047 |
11 | 581a956922 |
12 | 275b77b43b |
13 | 137ab2175c |
14 | 9269a5019 |
15 | 543ecca32 |
hex | 3273f07af |
13543344047 has 2 divisors, whose sum is σ = 13543344048. Its totient is φ = 13543344046.
The previous prime is 13543344019. The next prime is 13543344071. The reversal of 13543344047 is 74044334531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13543344047 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13543344047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13543344007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6771672023 + 6771672024.
It is an arithmetic number, because the mean of its divisors is an integer number (6771672024).
Almost surely, 213543344047 is an apocalyptic number.
13543344047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13543344047 is an equidigital number, since it uses as much as digits as its factorization.
13543344047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 241920, while the sum is 38.
Adding to 13543344047 its reverse (74044334531), we get a palindrome (87587678578).
The spelling of 13543344047 in words is "thirteen billion, five hundred forty-three million, three hundred forty-four thousand, forty-seven".
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