Base | Representation |
---|---|
bin | 11110110010110101001000… |
… | …001110001011011011000000 |
3 | 122202112101220021101022122111 |
4 | 132302311020032023123000 |
5 | 120222424140321433440 |
6 | 1200013413404345104 |
7 | 40345546032500434 |
oct | 3662651016133300 |
9 | 582471807338574 |
10 | 135434415421120 |
11 | 3a17645a812382 |
12 | 1323411b845194 |
13 | 5a75545051a9a |
14 | 25630bc7229c4 |
15 | 109ce5ec704ea |
hex | 7b2d4838b6c0 |
135434415421120 has 56 divisors (see below), whose sum is σ = 322505242845984. Its totient is φ = 54173423302656.
The previous prime is 135434415421117. The next prime is 135434415421121. The reversal of 135434415421120 is 21124514434531.
It is a Harshad number since it is a multiple of its sum of digits (40).
It is not an unprimeable number, because it can be changed into a prime (135434415421121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52702429 + ... + 55212451.
Almost surely, 2135434415421120 is an apocalyptic number.
135434415421120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
135434415421120 is an abundant number, since it is smaller than the sum of its proper divisors (187070827424864).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135434415421120 is a wasteful number, since it uses less digits than its factorization.
135434415421120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2678657 (or 2678647 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 40.
Adding to 135434415421120 its reverse (21124514434531), we get a palindrome (156558929855651).
The spelling of 135434415421120 in words is "one hundred thirty-five trillion, four hundred thirty-four billion, four hundred fifteen million, four hundred twenty-one thousand, one hundred twenty".
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