Base | Representation |
---|---|
bin | 11001001110100110… |
… | …01110011001110000 |
3 | 1021221220220100021111 |
4 | 30213103032121300 |
5 | 210214312044130 |
6 | 10115552203104 |
7 | 656432152123 |
oct | 144723163160 |
9 | 37856810244 |
10 | 13544253040 |
11 | 582041785a |
12 | 275bb39494 |
13 | 137b07c416 |
14 | 926b603ba |
15 | 54410c02a |
hex | 3274ce670 |
13544253040 has 80 divisors (see below), whose sum is σ = 31887084096. Its totient is φ = 5349888000.
The previous prime is 13544253029. The next prime is 13544253053. The reversal of 13544253040 is 4035244531.
13544253040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (80).
It is a junction number, because it is equal to n+sod(n) for n = 13544252993 and 13544253011.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2086600 + ... + 2093080.
Almost surely, 213544253040 is an apocalyptic number.
13544253040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13544253040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15943542048).
13544253040 is an abundant number, since it is smaller than the sum of its proper divisors (18342831056).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13544253040 is a wasteful number, since it uses less digits than its factorization.
13544253040 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6818 (or 6812 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 31.
Adding to 13544253040 its reverse (4035244531), we get a palindrome (17579497571).
The spelling of 13544253040 in words is "thirteen billion, five hundred forty-four million, two hundred fifty-three thousand, forty".
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