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13550040151 = 131103435421
BaseRepresentation
bin11001001111010010…
…10011010001010111
31021222022210100200221
430213221103101113
5210222302241101
610120320215211
7656532304144
oct144751232127
937868710627
1013550040151
11582370a79a
122761a6a507
13137c32754b
149278293cb
155448a1aa1
hex327a53457

13550040151 has 4 divisors (see below), whose sum is σ = 13653475704. Its totient is φ = 13446604600.

The previous prime is 13550040131. The next prime is 13550040181. The reversal of 13550040151 is 15104005531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13550040151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13550040131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51717580 + ... + 51717841.

It is an arithmetic number, because the mean of its divisors is an integer number (3413368926).

Almost surely, 213550040151 is an apocalyptic number.

13550040151 is a deficient number, since it is larger than the sum of its proper divisors (103435553).

13550040151 is a wasteful number, since it uses less digits than its factorization.

13550040151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103435552.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 13550040151 its reverse (15104005531), we get a palindrome (28654045682).

The spelling of 13550040151 in words is "thirteen billion, five hundred fifty million, forty thousand, one hundred fifty-one".

Divisors: 1 131 103435421 13550040151