Base | Representation |
---|---|
bin | 11001001111010100… |
… | …11010010101101111 |
3 | 1021222100100011000021 |
4 | 30213222122111233 |
5 | 210222341044442 |
6 | 10120330343011 |
7 | 656534625625 |
oct | 144752322557 |
9 | 37870304007 |
10 | 13550331247 |
11 | 5823899472 |
12 | 2761b8aa67 |
13 | 137c3c9bab |
14 | 9278a3515 |
15 | 54490ce67 |
hex | 327a9a56f |
13550331247 has 2 divisors, whose sum is σ = 13550331248. Its totient is φ = 13550331246.
The previous prime is 13550331181. The next prime is 13550331259. The reversal of 13550331247 is 74213305531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13550331247 - 215 = 13550298479 is a prime.
It is a super-2 number, since 2×135503312472 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13550731247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775165623 + 6775165624.
It is an arithmetic number, because the mean of its divisors is an integer number (6775165624).
Almost surely, 213550331247 is an apocalyptic number.
13550331247 is a deficient number, since it is larger than the sum of its proper divisors (1).
13550331247 is an equidigital number, since it uses as much as digits as its factorization.
13550331247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 34.
Adding to 13550331247 its reverse (74213305531), we get a palindrome (87763636778).
The spelling of 13550331247 in words is "thirteen billion, five hundred fifty million, three hundred thirty-one thousand, two hundred forty-seven".
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