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135505503353333 is a prime number
BaseRepresentation
bin11110110011110111010101…
…011001000111100111110101
3122202210012101111212102221202
4132303313111121013213311
5120230110232324301313
61200110211401422245
740353643460112221
oct3663672531074765
9582705344772852
10135505503353333
113a1a361a026a83
1213245a5aa9a985
135a7c1639b32b9
142566703a15781
15109ec20b31558
hex7b3dd56479f5

135505503353333 has 2 divisors, whose sum is σ = 135505503353334. Its totient is φ = 135505503353332.

The previous prime is 135505503353293. The next prime is 135505503353383. The reversal of 135505503353333 is 333353305505531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133645206492004 + 1860296861329 = 11560502^2 + 1363927^2 .

It is a cyclic number.

It is not a de Polignac number, because 135505503353333 - 210 = 135505503352309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135505503353383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67752751676666 + 67752751676667.

It is an arithmetic number, because the mean of its divisors is an integer number (67752751676667).

Almost surely, 2135505503353333 is an apocalyptic number.

It is an amenable number.

135505503353333 is a deficient number, since it is larger than the sum of its proper divisors (1).

135505503353333 is an equidigital number, since it uses as much as digits as its factorization.

135505503353333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6834375, while the sum is 47.

Adding to 135505503353333 its reverse (333353305505531), we get a palindrome (468858808858864).

The spelling of 135505503353333 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred three million, three hundred fifty-three thousand, three hundred thirty-three".