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1355113545077 is a prime number
BaseRepresentation
bin10011101110000011000…
…011111011110101110101
311210112210012012121222102
4103232003003323311311
5134200233031420302
62514310334111445
7166621656036665
oct23560303736565
94715705177872
101355113545077
114827782a5356
1219a76894b585
139aa2c39c886
14498330961a5
15253b269e702
hex13b830fbd75

1355113545077 has 2 divisors, whose sum is σ = 1355113545078. Its totient is φ = 1355113545076.

The previous prime is 1355113545029. The next prime is 1355113545119. The reversal of 1355113545077 is 7705453115531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1084345259761 + 270768285316 = 1041319^2 + 520354^2 .

It is an emirp because it is prime and its reverse (7705453115531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1355113545077 - 222 = 1355109350773 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355113505077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677556772538 + 677556772539.

It is an arithmetic number, because the mean of its divisors is an integer number (677556772539).

Almost surely, 21355113545077 is an apocalyptic number.

It is an amenable number.

1355113545077 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355113545077 is an equidigital number, since it uses as much as digits as its factorization.

1355113545077 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1102500, while the sum is 47.

The spelling of 1355113545077 in words is "one trillion, three hundred fifty-five billion, one hundred thirteen million, five hundred forty-five thousand, seventy-seven".