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13551550037 is a prime number
BaseRepresentation
bin11001001111011110…
…00011111001010101
31021222102122001212122
430213233003321111
5210223144100122
610120412425325
7656551163144
oct144757037125
937872561778
1013551550037
115824551133
122762478245
13137c73587c
14927add75b
15544a9e142
hex327bc3e55

13551550037 has 2 divisors, whose sum is σ = 13551550038. Its totient is φ = 13551550036.

The previous prime is 13551550027. The next prime is 13551550039. The reversal of 13551550037 is 73005515531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13541045956 + 10504081 = 116366^2 + 3241^2 .

It is a cyclic number.

It is not a de Polignac number, because 13551550037 - 212 = 13551545941 is a prime.

Together with 13551550039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13551549979 and 13551550006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13551550039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775775018 + 6775775019.

It is an arithmetic number, because the mean of its divisors is an integer number (6775775019).

Almost surely, 213551550037 is an apocalyptic number.

It is an amenable number.

13551550037 is a deficient number, since it is larger than the sum of its proper divisors (1).

13551550037 is an equidigital number, since it uses as much as digits as its factorization.

13551550037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 39375, while the sum is 35.

The spelling of 13551550037 in words is "thirteen billion, five hundred fifty-one million, five hundred fifty thousand, thirty-seven".