Base | Representation |
---|---|
bin | 11110110100001001000010… |
… | …100000111110111000111010 |
3 | 122202212000110101202101011211 |
4 | 132310021002200332320322 |
5 | 120230413201041003232 |
6 | 1200123034025513334 |
7 | 40355215540001320 |
oct | 3664110240767072 |
9 | 582760411671154 |
10 | 135524514000442 |
11 | 3a200695044586 |
12 | 1324968564284a |
13 | 5a80ba340b008 |
14 | 25675c8761d10 |
15 | 10a0484ac0a47 |
hex | 7b424283ee3a |
135524514000442 has 64 divisors (see below), whose sum is σ = 244733349369600. Its totient is φ = 54984989306880.
The previous prime is 135524514000397. The next prime is 135524514000481. The reversal of 135524514000442 is 244000415425531.
It is a junction number, because it is equal to n+sod(n) for n = 135524514000395 and 135524514000404.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2946866784 + ... + 2946912772.
It is an arithmetic number, because the mean of its divisors is an integer number (3823958583900).
Almost surely, 2135524514000442 is an apocalyptic number.
135524514000442 is a deficient number, since it is larger than the sum of its proper divisors (109208835369158).
135524514000442 is a wasteful number, since it uses less digits than its factorization.
135524514000442 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53831.
The product of its (nonzero) digits is 384000, while the sum is 40.
Adding to 135524514000442 its reverse (244000415425531), we get a palindrome (379524929425973).
The spelling of 135524514000442 in words is "one hundred thirty-five trillion, five hundred twenty-four billion, five hundred fourteen million, four hundred forty-two", and thus it is an aban number.
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