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135531242411231 is a prime number
BaseRepresentation
bin11110110100001111010011…
…100011110101010011011111
3122202212122211022110001121102
4132310033103203311103133
5120231020441024124411
61200130105423023315
740355544350360312
oct3664172343652337
9582778738401542
10135531242411231
113a20352805a157
121324aa42a3ab3b
135a81706382984
142567a661c2979
1510a072a63dd3b
hex7b43d38f54df

135531242411231 has 2 divisors, whose sum is σ = 135531242411232. Its totient is φ = 135531242411230.

The previous prime is 135531242411209. The next prime is 135531242411239. The reversal of 135531242411231 is 132114242135531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135531242411231 - 242 = 131133195900127 is a prime.

It is a super-2 number, since 2×1355312424112312 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135531242411239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67765621205615 + 67765621205616.

It is an arithmetic number, because the mean of its divisors is an integer number (67765621205616).

Almost surely, 2135531242411231 is an apocalyptic number.

135531242411231 is a deficient number, since it is larger than the sum of its proper divisors (1).

135531242411231 is an equidigital number, since it uses as much as digits as its factorization.

135531242411231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 86400, while the sum is 38.

Adding to 135531242411231 its reverse (132114242135531), we get a palindrome (267645484546762).

The spelling of 135531242411231 in words is "one hundred thirty-five trillion, five hundred thirty-one billion, two hundred forty-two million, four hundred eleven thousand, two hundred thirty-one".