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1355411102623 is a prime number
BaseRepresentation
bin10011101110010100110…
…011000001101110011111
311210120112221010010012021
4103232110303001232133
5134201340220240443
62514400043521011
7166632231164464
oct23562463015637
94716487103167
101355411102623
11482910260786
1219a830529167
139aa78c23a26
14498607d166b
15253cd8799ed
hex13b94cc1b9f

1355411102623 has 2 divisors, whose sum is σ = 1355411102624. Its totient is φ = 1355411102622.

The previous prime is 1355411102581. The next prime is 1355411102627. The reversal of 1355411102623 is 3262011145531.

It is a strong prime.

It is an emirp because it is prime and its reverse (3262011145531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1355411102623 - 213 = 1355411094431 is a prime.

It is a super-2 number, since 2×13554111026232 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1355411102627) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677705551311 + 677705551312.

It is an arithmetic number, because the mean of its divisors is an integer number (677705551312).

Almost surely, 21355411102623 is an apocalyptic number.

1355411102623 is a deficient number, since it is larger than the sum of its proper divisors (1).

1355411102623 is an equidigital number, since it uses as much as digits as its factorization.

1355411102623 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 34.

The spelling of 1355411102623 in words is "one trillion, three hundred fifty-five billion, four hundred eleven million, one hundred two thousand, six hundred twenty-three".