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135544430513 is a prime number
BaseRepresentation
bin111111000111100010…
…0111101111110110001
3110221212022202111110002
41332033010331332301
54210043333234023
6142133535315345
712535626435542
oct1761704757661
9427768674402
10135544430513
115253632a908
122232967bb55
13ca2177384b
1467bb9aa4c9
1537d49acb28
hex1f8f13dfb1

135544430513 has 2 divisors, whose sum is σ = 135544430514. Its totient is φ = 135544430512.

The previous prime is 135544430471. The next prime is 135544430551. The reversal of 135544430513 is 315034445531.

It is an a-pointer prime, because the next prime (135544430551) can be obtained adding 135544430513 to its sum of digits (38).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108282457969 + 27261972544 = 329063^2 + 165112^2 .

It is a cyclic number.

It is not a de Polignac number, because 135544430513 - 232 = 131249463217 is a prime.

It is not a weakly prime, because it can be changed into another prime (135544430563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67772215256 + 67772215257.

It is an arithmetic number, because the mean of its divisors is an integer number (67772215257).

Almost surely, 2135544430513 is an apocalyptic number.

It is an amenable number.

135544430513 is a deficient number, since it is larger than the sum of its proper divisors (1).

135544430513 is an equidigital number, since it uses as much as digits as its factorization.

135544430513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 38.

The spelling of 135544430513 in words is "one hundred thirty-five billion, five hundred forty-four million, four hundred thirty thousand, five hundred thirteen".