Base | Representation |
---|---|
bin | 11110110100100001000011… |
… | …100000010011001100010010 |
3 | 122202221111000111102022202001 |
4 | 132310201003200103030102 |
5 | 120231324003400334300 |
6 | 1200142540501544214 |
7 | 40360120543543033 |
oct | 3664410340231422 |
9 | 582844014368661 |
10 | 135550300402450 |
11 | 3a21061787401a |
12 | 1325268141506a |
13 | 5a83452845c5b |
14 | 2568953334a8a |
15 | 10a0e9383116a |
hex | 7b4843813312 |
135550300402450 has 24 divisors (see below), whose sum is σ = 252123973317540. Its totient is φ = 54220031006400.
The previous prime is 135550300402423. The next prime is 135550300402501. The reversal of 135550300402450 is 54204003055531.
It can be written as a sum of positive squares in 6 ways, for example, as 62521329003849 + 73028971398601 = 7907043^2 + 8545699^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 34463880 + ... + 38195020.
Almost surely, 2135550300402450 is an apocalyptic number.
135550300402450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135550300402450 is a deficient number, since it is larger than the sum of its proper divisors (116573672915090).
135550300402450 is a wasteful number, since it uses less digits than its factorization.
135550300402450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4457742 (or 4457737 counting only the distinct ones).
The product of its (nonzero) digits is 180000, while the sum is 37.
Adding to 135550300402450 its reverse (54204003055531), we get a palindrome (189754303457981).
The spelling of 135550300402450 in words is "one hundred thirty-five trillion, five hundred fifty billion, three hundred million, four hundred two thousand, four hundred fifty".
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