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135550401044101 is a prime number
BaseRepresentation
bin11110110100100001001001…
…100000001101111010000101
3122202221111021111210110010121
4132310201021200031322011
5120231324210131402401
61200142554455021541
740360123205146651
oct3664411140157205
9582844244713117
10135550401044101
113a21066966363a
12132526ab06a8b1
135a8346a652824
142568962851a61
1510a0e9c5b0ca1
hex7b484980de85

135550401044101 has 2 divisors, whose sum is σ = 135550401044102. Its totient is φ = 135550401044100.

The previous prime is 135550401044083. The next prime is 135550401044269. The reversal of 135550401044101 is 101440104055531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116341894716100 + 19208506328001 = 10786190^2 + 4382751^2 .

It is a cyclic number.

It is not a de Polignac number, because 135550401044101 - 213 = 135550401035909 is a prime.

It is a super-2 number, since 2×1355504010441012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135550401042101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67775200522050 + 67775200522051.

It is an arithmetic number, because the mean of its divisors is an integer number (67775200522051).

Almost surely, 2135550401044101 is an apocalyptic number.

It is an amenable number.

135550401044101 is a deficient number, since it is larger than the sum of its proper divisors (1).

135550401044101 is an equidigital number, since it uses as much as digits as its factorization.

135550401044101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 135550401044101 its reverse (101440104055531), we get a palindrome (236990505099632).

The spelling of 135550401044101 in words is "one hundred thirty-five trillion, five hundred fifty billion, four hundred one million, forty-four thousand, one hundred one".