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135607325489 is a prime number
BaseRepresentation
bin111111001001011010…
…0111001001100110001
3110222000201002220010122
41332102310321030301
54210210433403424
6142144103340025
712540322151036
oct1762264711461
9428021086118
10135607325489
1152568888829
1222346751615
13ca317c53cc
1467c609d38d
1537da28345e
hex1f92d39331

135607325489 has 2 divisors, whose sum is σ = 135607325490. Its totient is φ = 135607325488.

The previous prime is 135607325467. The next prime is 135607325563. The reversal of 135607325489 is 984523706531.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135264335089 + 342990400 = 367783^2 + 18520^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135607325489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 135607325489.

It is not a weakly prime, because it can be changed into another prime (135607325419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67803662744 + 67803662745.

It is an arithmetic number, because the mean of its divisors is an integer number (67803662745).

It is a 1-persistent number, because it is pandigital, but 2⋅135607325489 = 271214650978 is not.

Almost surely, 2135607325489 is an apocalyptic number.

It is an amenable number.

135607325489 is a deficient number, since it is larger than the sum of its proper divisors (1).

135607325489 is an equidigital number, since it uses as much as digits as its factorization.

135607325489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5443200, while the sum is 53.

The spelling of 135607325489 in words is "one hundred thirty-five billion, six hundred seven million, three hundred twenty-five thousand, four hundred eighty-nine".