Base | Representation |
---|---|
bin | 1100010101010111111011… |
… | …1010011110010010001111 |
3 | 1210000110012011122110122112 |
4 | 3011111332322132102033 |
5 | 3234142111244323322 |
6 | 44501554414334235 |
7 | 2566526446435052 |
oct | 305257672362217 |
9 | 53013164573575 |
10 | 13561341011087 |
11 | 4359372503781 |
12 | 16303417ba37b |
13 | 774aa132a14c |
14 | 34c52dc56a99 |
15 | 187b6560e5e2 |
hex | c557ee9e48f |
13561341011087 has 2 divisors, whose sum is σ = 13561341011088. Its totient is φ = 13561341011086.
The previous prime is 13561341011081. The next prime is 13561341011089. The reversal of 13561341011087 is 78011014316531.
It is a strong prime.
It is an emirp because it is prime and its reverse (78011014316531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13561341011087 - 212 = 13561341006991 is a prime.
Together with 13561341011089, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13561341011081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6780670505543 + 6780670505544.
It is an arithmetic number, because the mean of its divisors is an integer number (6780670505544).
Almost surely, 213561341011087 is an apocalyptic number.
13561341011087 is a deficient number, since it is larger than the sum of its proper divisors (1).
13561341011087 is an equidigital number, since it uses as much as digits as its factorization.
13561341011087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 13561341011087 in words is "thirteen trillion, five hundred sixty-one billion, three hundred forty-one million, eleven thousand, eighty-seven".
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