Search a number
-
+
135652721240438 = 272872819307499
BaseRepresentation
bin11110110110000000011100…
…010000110010100101110110
3122210022021101101021222101222
4132312000130100302211312
5120240013233114143223
61200301555543550342
740400404614364163
oct3666003420624566
9583267341258358
10135652721240438
113a24aaa5754576
121326a4a5a5b3b2
135a8ccc5a58cbc
14256d8ababb06a
1510a398a35b0c8
hex7b601c432976

135652721240438 has 8 divisors (see below), whose sum is σ = 203479131645000. Its totient is φ = 67826344025440.

The previous prime is 135652721240389. The next prime is 135652721240459. The reversal of 135652721240438 is 834042127256531.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 135652721240438.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9920813 + ... + 19228311.

It is an arithmetic number, because the mean of its divisors is an integer number (25434891455625).

Almost surely, 2135652721240438 is an apocalyptic number.

135652721240438 is a deficient number, since it is larger than the sum of its proper divisors (67826410404562).

135652721240438 is an equidigital number, since it uses as much as digits as its factorization.

135652721240438 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16594782.

The product of its (nonzero) digits is 9676800, while the sum is 53.

Adding to 135652721240438 its reverse (834042127256531), we get a palindrome (969694848496969).

The spelling of 135652721240438 in words is "one hundred thirty-five trillion, six hundred fifty-two billion, seven hundred twenty-one million, two hundred forty thousand, four hundred thirty-eight".

Divisors: 1 2 7287281 9307499 14574562 18614998 67826360620219 135652721240438