1356724948400 has 120 divisors (see below), whose sum is σ = 3339796958064. Its totient is φ = 529332428800.

The previous prime is 1356724948399. The next prime is 1356724948433. The reversal of 1356724948400 is 48494276531.

It is a super-2 number, since 2×1356724948400² (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 112055147 + ... + 112067253.

It is a 1-persistent number, because it is pandigital, but 2⋅1356724948400 = 2713449896800 is not.

Almost surely, 2^{1356724948400} is an apocalyptic number.

1356724948400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1356724948400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1669898479032).

1356724948400 is an abundant number, since it is smaller than the sum of its proper divisors (1983072009664).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1356724948400 is a wasteful number, since it uses less digits than its factorization.

1356724948400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18999 (or 18988 counting only the distinct ones).

The product of its (nonzero) digits is 5806080, while the sum is 53.

The spelling of 1356724948400 in words is "one trillion, three hundred fifty-six billion, seven hundred twenty-four million, nine hundred forty-eight thousand, four hundred".