Base | Representation |
---|---|
bin | 10011101111100011000… |
… | …110111100110111101001 |
3 | 11210200221111100101212002 |
4 | 103233203012330313221 |
5 | 134212033041322312 |
6 | 2515134300100345 |
7 | 200006623533014 |
oct | 23574306746751 |
9 | 4720844311762 |
10 | 1356724948457 |
11 | 48342495558a |
12 | 19ab385346b5 |
13 | 9ac28198bb8 |
14 | 499470b837b |
15 | 25458da24c2 |
hex | 13be31bcde9 |
1356724948457 has 2 divisors, whose sum is σ = 1356724948458. Its totient is φ = 1356724948456.
The previous prime is 1356724948433. The next prime is 1356724948459. The reversal of 1356724948457 is 7548494276531.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1096751413081 + 259973535376 = 1047259^2 + 509876^2 .
It is a cyclic number.
It is not a de Polignac number, because 1356724948457 - 240 = 257213320681 is a prime.
Together with 1356724948459, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1356724948393 and 1356724948402.
It is not a weakly prime, because it can be changed into another prime (1356724948459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678362474228 + 678362474229.
It is an arithmetic number, because the mean of its divisors is an integer number (678362474229).
Almost surely, 21356724948457 is an apocalyptic number.
It is an amenable number.
1356724948457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1356724948457 is an equidigital number, since it uses as much as digits as its factorization.
1356724948457 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 203212800, while the sum is 65.
The spelling of 1356724948457 in words is "one trillion, three hundred fifty-six billion, seven hundred twenty-four million, nine hundred forty-eight thousand, four hundred fifty-seven".
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