Base | Representation |
---|---|
bin | 10011101111111110010… |
… | …011011111111111110100 |
3 | 11210202010021220112201112 |
4 | 103233332103133333310 |
5 | 134214001343113100 |
6 | 2515251435414152 |
7 | 200024134024136 |
oct | 23577623377764 |
9 | 4722107815645 |
10 | 1357181222900 |
11 | 4836394672a8 |
12 | 19b0452b4358 |
13 | 9ac9b881789 |
14 | 4998b92b056 |
15 | 25483e7eb35 |
hex | 13bfe4dfff4 |
1357181222900 has 72 divisors (see below), whose sum is σ = 2972010654144. Its totient is φ = 537911718400.
The previous prime is 1357181222893. The next prime is 1357181222959. The reversal of 1357181222900 is 92221817531.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 43636355 + ... + 43667445.
It is an arithmetic number, because the mean of its divisors is an integer number (41277925752).
Almost surely, 21357181222900 is an apocalyptic number.
1357181222900 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1357181222900, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1486005327072).
1357181222900 is an abundant number, since it is smaller than the sum of its proper divisors (1614829431244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1357181222900 is a wasteful number, since it uses less digits than its factorization.
1357181222900 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35081 (or 35074 counting only the distinct ones).
The product of its (nonzero) digits is 60480, while the sum is 41.
The spelling of 1357181222900 in words is "one trillion, three hundred fifty-seven billion, one hundred eighty-one million, two hundred twenty-two thousand, nine hundred".
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