Search a number
-
+
1357968719621 is a prime number
BaseRepresentation
bin10011110000101101001…
…111100011111100000101
311210211011011201112010202
4103300231033203330011
5134222104443011441
62515501530300245
7200052505444013
oct23605517437405
94724134645122
101357968719621
11483a02a38238
1219b224b87685
139b095a77577
1449a2435d8b3
15254cd18719b
hex13c2d3e3f05

1357968719621 has 2 divisors, whose sum is σ = 1357968719622. Its totient is φ = 1357968719620.

The previous prime is 1357968719609. The next prime is 1357968719633. The reversal of 1357968719621 is 1269178697531.

It is a balanced prime because it is at equal distance from previous prime (1357968719609) and next prime (1357968719633).

It can be written as a sum of positive squares in only one way, i.e., 881137038721 + 476831680900 = 938689^2 + 690530^2 .

It is a cyclic number.

It is not a de Polignac number, because 1357968719621 - 214 = 1357968703237 is a prime.

It is a super-2 number, since 2×13579687196212 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1357968619621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 678984359810 + 678984359811.

It is an arithmetic number, because the mean of its divisors is an integer number (678984359811).

Almost surely, 21357968719621 is an apocalyptic number.

It is an amenable number.

1357968719621 is a deficient number, since it is larger than the sum of its proper divisors (1).

1357968719621 is an equidigital number, since it uses as much as digits as its factorization.

1357968719621 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34292160, while the sum is 65.

The spelling of 1357968719621 in words is "one trillion, three hundred fifty-seven billion, nine hundred sixty-eight million, seven hundred nineteen thousand, six hundred twenty-one".