Base | Representation |
---|---|
bin | 11110111001100000001001… |
… | …100011000110010100000000 |
3 | 122211011020101121212200022000 |
4 | 132321200021203012110000 |
5 | 120302432202403110110 |
6 | 1201004203105344000 |
7 | 40423640242403550 |
oct | 3671401143062400 |
9 | 584136347780260 |
10 | 135892925441280 |
11 | 3a332958765937 |
12 | 132a8b61938000 |
13 | 5aa9856525b17 |
14 | 257b377523160 |
15 | 10a9d481a11c0 |
hex | 7b98098c6500 |
135892925441280 has 1728 divisors, whose sum is σ = 561441351905280. Its totient is φ = 30489227034624.
The previous prime is 135892925441267. The next prime is 135892925441293. The reversal of 135892925441280 is 82144529298531.
135892925441280 is a `hidden beast` number, since 1 + 3 + 5 + 8 + 9 + 2 + 9 + 2 + 544 + 1 + 2 + 80 = 666.
135892925441280 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (135892925441267) and next prime (135892925441293).
It is a tau number, because it is divible by the number of its divisors (1728).
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 516703138429 + ... + 516703138691.
It is an arithmetic number, because the mean of its divisors is an integer number (324908189760).
Almost surely, 2135892925441280 is an apocalyptic number.
135892925441280 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 135892925441280, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (280720675952640).
135892925441280 is an abundant number, since it is smaller than the sum of its proper divisors (425548426464000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135892925441280 is an equidigital number, since it uses as much as digits as its factorization.
135892925441280 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 721 (or 604 counting only the distinct ones).
The product of its (nonzero) digits is 49766400, while the sum is 63.
The spelling of 135892925441280 in words is "one hundred thirty-five trillion, eight hundred ninety-two billion, nine hundred twenty-five million, four hundred forty-one thousand, two hundred eighty".
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