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135935604047 is a prime number
BaseRepresentation
bin111111010011001100…
…1001011010101001111
3110222212120211011122202
41332212121023111033
54211344003312142
6142240431432115
712551416366265
oct1764631132517
9428776734582
10135935604047
1152717117321
122241868563b
13ca84814789
146817914435
153808ecb032
hex1fa664b54f

135935604047 has 2 divisors, whose sum is σ = 135935604048. Its totient is φ = 135935604046.

The previous prime is 135935603981. The next prime is 135935604053. The reversal of 135935604047 is 740406539531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 135935604047 - 212 = 135935599951 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135935603992 and 135935604010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135935604947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67967802023 + 67967802024.

It is an arithmetic number, because the mean of its divisors is an integer number (67967802024).

Almost surely, 2135935604047 is an apocalyptic number.

135935604047 is a deficient number, since it is larger than the sum of its proper divisors (1).

135935604047 is an equidigital number, since it uses as much as digits as its factorization.

135935604047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 47.

The spelling of 135935604047 in words is "one hundred thirty-five billion, nine hundred thirty-five million, six hundred four thousand, forty-seven".