Base | Representation |
---|---|
bin | 111111010011001100… |
… | …1001011010101001111 |
3 | 110222212120211011122202 |
4 | 1332212121023111033 |
5 | 4211344003312142 |
6 | 142240431432115 |
7 | 12551416366265 |
oct | 1764631132517 |
9 | 428776734582 |
10 | 135935604047 |
11 | 52717117321 |
12 | 2241868563b |
13 | ca84814789 |
14 | 6817914435 |
15 | 3808ecb032 |
hex | 1fa664b54f |
135935604047 has 2 divisors, whose sum is σ = 135935604048. Its totient is φ = 135935604046.
The previous prime is 135935603981. The next prime is 135935604053. The reversal of 135935604047 is 740406539531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135935604047 - 212 = 135935599951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 135935603992 and 135935604010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135935604947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67967802023 + 67967802024.
It is an arithmetic number, because the mean of its divisors is an integer number (67967802024).
Almost surely, 2135935604047 is an apocalyptic number.
135935604047 is a deficient number, since it is larger than the sum of its proper divisors (1).
135935604047 is an equidigital number, since it uses as much as digits as its factorization.
135935604047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1360800, while the sum is 47.
The spelling of 135935604047 in words is "one hundred thirty-five billion, nine hundred thirty-five million, six hundred four thousand, forty-seven".
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